+0  
 
0
2044
1
avatar+488 

What is the ratio of the volume of cone $A$ to the volume of cone $B$? Express your answer as a common fraction.

IMAGE

https://latex.artofproblemsolving.com/d/6/2/d62f494a22d0726aa38320488b044e6b2b2ea8f9.png

 Dec 6, 2017

Best Answer 

 #1
avatar+9460 
+2

 

volume of cone  A  =  \(\frac13\cdot\pi\cdot14.8^2\cdot28.3\)

 

volume of cone  B  =  \(\frac13\cdot\pi\cdot28.3^2\cdot14.8\)

 

\(\frac{\text{volume of cone A}}{\text{volume of cone B}}\,=\,\frac{\frac13\cdot\pi\cdot14.8^2\cdot28.3}{\frac13\cdot\pi\cdot28.3^2\cdot14.8}\,=\,\frac{14.8^2\cdot28.3}{28.3^2\cdot14.8}\,=\,\frac{14.8}{28.3}\,=\,\frac{148}{283}\)

 Dec 6, 2017
 #1
avatar+9460 
+2
Best Answer

 

volume of cone  A  =  \(\frac13\cdot\pi\cdot14.8^2\cdot28.3\)

 

volume of cone  B  =  \(\frac13\cdot\pi\cdot28.3^2\cdot14.8\)

 

\(\frac{\text{volume of cone A}}{\text{volume of cone B}}\,=\,\frac{\frac13\cdot\pi\cdot14.8^2\cdot28.3}{\frac13\cdot\pi\cdot28.3^2\cdot14.8}\,=\,\frac{14.8^2\cdot28.3}{28.3^2\cdot14.8}\,=\,\frac{14.8}{28.3}\,=\,\frac{148}{283}\)

hectictar Dec 6, 2017

8 Online Users

avatar
avatar
avatar