+0  
 
0
851
1
avatar+267 

Solved it nevermind thanks :D

 Nov 13, 2017
edited by WhichWitchIsWhich  Nov 13, 2017
 #1
avatar+128079 
+1

x^3-x^2+x+1 =x^3+x^2+x-1 

 

Subtract x^3, x   from each side

 

-x^2 + x + 1  =  x^2 - 1

 

-x^2 + 1  = x^2 - 1    rearange as

 

0  =  2x^2 - 2

 

2x^2 - 2  = 0     divide through by 2

 

x^2 - 1  = 0    factor

y = (1)^3 + (1)^2 + 1 - 1  =

(x + 1) ( x - 1)  = 0 

 

Set each factor to 0 and solve for x

 

And  x = 1   or x = -1

 

And using  x^3+x^2+x-1   

 

y = (1)^3 + (1)^2 + 1 - 1  =  2

 

y = (-1)^3 + (-1)^2 - 1 - 1  =  -2

 

So the solutions are  (1, 2)  and (-1. -2)

 

 

cool cool cool  

 Nov 13, 2017

6 Online Users

avatar
avatar
avatar
avatar