ummm Yeah I need even more help

-2x²  =  -(5x + 4)

                               Distribute  -1  to the terms in parenthesees.

-2x²  =  -5x - 4

                               Add  2x²  to both sides of the equation.

0  =  2x² - 5x - 4

2x² - 5x - 4  =  0

2x² + -5x + -4  =  0

This is a quadratic equation. We can use the quadratic formula to solve for  x .

The quadratic formula says that....

If     ax² + bx + c  =  0     then     $x=\frac{-\mathbf{\color{blue}b}\pm\sqrt{\mathbf{\color{blue}b}^2-4\mathbf{\color{Magenta}a}\mathbf{\color{Green}c}}}{2\mathbf{\color{Magenta}a}}$

So...

Since     2x² + -5x + -4  =  0     then     $x=\frac{-(\mathbf{\color{blue}-5})\pm\sqrt{\mathbf{(\color{blue}-5})^2-4(\mathbf{\color{Magenta}2})(\mathbf{\color{Green}-4})}}{2(\mathbf{\color{Magenta}2})}$

$x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-4)}}{2(2)}\\~\\ x=\frac{5\pm\sqrt{25+32}}{4}\\~\\ x=\frac{5\pm\sqrt{57}}{4}\\~\\ x=\frac{5+\sqrt{57}}{4}\qquad\text{or}\qquad x=\frac{5-\sqrt{57}}{4}$