Trigonometry

A boy flying a kite lets out 300ft of string which makes an angle of 38 degrees with the ground. Assuming that the string is straight, how high above the ground is the kite?

I think:

 you have hyp. 300 ft. and angle 38 degrees. The question is asking for opposite of 38 degrees

So what deals with the opposite and hyp.

$sin=\frac oh \\ sin(38)=\frac{O}{300} \\ sin(38)*300=O \\O=184.6984425976974839\dots$

Thanks Solveit, 

So that means that the kite is approx 184.7 feet above the ground !

Don't forget to put the units in your final answer     

Thank you for answering