In the figure, BA = AD = DC and point D is on segment BC. The measure of angle ACD is 25 degrees. What is the measure of angle ABC?
+179 Both of the separate triangles in this figure are isosceles, as two of their sides are the same.
Thus, we know that $\angle{ACD} = \angle{DAC} = 25$.
From this, we know that $\angle{ADC} = 180 - 25 \cdot 2$, for the two other angles in the triangle. Thus, $\angle{ADC} = 130$.
Because $\angle{ADB}$ and $\angle{ADC}$ are supplementary, we know that $\angle{ADB} = 180 - 130 = 50$.
Finally, since $\triangle{ABD}$ is isosceles, we know that $\angle{ABC}$ is also $\boxed{50}$.
