In triangle ABC, D is a point on ¯BC such that BD=DC=DA. If ∠ABC=45∘, then how many degrees are in ∠ACB?
I think the answer is 45 degrees, because angle abc is 45, and because BD = BC = BA, I think it is an isosceles. I'm not sure.
By SAS, triangle BDA is similar to triangle CDA
Angle ABD = Angle ACD = Angle ACB = 45
Another way would be to note that ADB and ADC are congruent, which proves that the angle is 45 as well.