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The product of two consecutive odd integers is 99. Find the integers. Show work. Correct answer with very little work will receive no credit.

 Nov 29, 2021
 #1
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We can first set the smaller one to be a, and the larger one to be a+2. Now, the problem tells us that a(a+2)=99. Multiplying out and rearranging, we obtain the equation a2+2a99=0. We can factor this as (a9)(a+11)=0, so the solutions are a=11 or a=9. This means that the odd integers could either be 11,9, or they could be 9,11.

 

Hope this helped laugh

 Nov 29, 2021

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