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The path of a fired projectile is modeled by the function f(x)=x(2x+8) where x is the height (in feet) and f(x) in the distance(in feet). If the distance is 24 feet, what is the height of the projectile?

 Jan 29, 2015

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 #1
avatar+26399 
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The path of a fired projectile is modeled by the function f(x)=x(2x+8) where x is the height (in feet) and f(x) in the distance(in feet). If the distance is 24 feet, what is the height of the projectile ?

f(x)=x(2x+8)f(x)=2424=x(2x+8)24=2x2+8x|:212=x2+4x|120=x2+4x12x2+4x12=0factoring(x2)=0(x+6)=0=0x2=0we havex=2okayx+6=0we havex=6no solution!

the height of the projectile is 2 feet.

 Jan 29, 2015
 #1
avatar+26399 
+10
Best Answer

The path of a fired projectile is modeled by the function f(x)=x(2x+8) where x is the height (in feet) and f(x) in the distance(in feet). If the distance is 24 feet, what is the height of the projectile ?

f(x)=x(2x+8)f(x)=2424=x(2x+8)24=2x2+8x|:212=x2+4x|120=x2+4x12x2+4x12=0factoring(x2)=0(x+6)=0=0x2=0we havex=2okayx+6=0we havex=6no solution!

the height of the projectile is 2 feet.

heureka Jan 29, 2015

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