The path of a fired projectile is modeled by the function f(x)=x(2x+8) where x is the height (in feet) and f(x) in the distance(in feet). If the distance is 24 feet, what is the height of the projectile?
The path of a fired projectile is modeled by the function f(x)=x(2x+8) where x is the height (in feet) and f(x) in the distance(in feet). If the distance is 24 feet, what is the height of the projectile ?
f(x)=x(2x+8)f(x)=2424=x(2x+8)24=2x2+8x|:212=x2+4x|−120=x2+4x−12x2+4x−12=0factoring(x−2)⏟=0(x+6)⏟=0=0x−2=0we havex=2okayx+6=0we havex=−6no solution!
the height of the projectile is 2 feet.
The path of a fired projectile is modeled by the function f(x)=x(2x+8) where x is the height (in feet) and f(x) in the distance(in feet). If the distance is 24 feet, what is the height of the projectile ?
f(x)=x(2x+8)f(x)=2424=x(2x+8)24=2x2+8x|:212=x2+4x|−120=x2+4x−12x2+4x−12=0factoring(x−2)⏟=0(x+6)⏟=0=0x−2=0we havex=2okayx+6=0we havex=−6no solution!
the height of the projectile is 2 feet.