The point A has the coodinates (2 , 5)
The point B has the coodinates (6 , 7)
The equation of AB is y = 1/2x + 4
Find the equation of the perpendicular bisector to AB
We need to find the mid-point of AB....this is :
[ (2 + 6)/2, (5 + 7) /2) = ( 8 / 2, 12 / 2) = (4, 6)
The perpendicular bisector will go through this point...and it will have a slope of -2
So .....its equation is
y = -2 ( x - 4) + 6
y = -2x + 8 + 6
y = -2x + 14
Can you explain where the x-4 came from please
The equation is
y = m(x - h) + k
Where m is the slope of the perpendicular bisector.....and ( h, k) = ( 4, 6) which is a point on the perpedicular bisector....in this case, it's the midpoint of AB
+845 
