suppose a capacitor has XC =-8800 Ohms at f = 830 kHz. What is C?

suppose a capacitor has XC =-8800 Ohms at f = 830 kHz. What is C ?

$$\boxed{X_C = \dfrac{ 1 }{ 2 \cdot \pi \cdot f \cdot C } \qquad C = \dfrac{ 1 }{ 2 \cdot \pi \cdot f \cdot X_C } } \\$$

Capacitive reactance, where: X_C = reactance in ohms (ohm), f = frequency in hertz (Hz), C = capacitance in farads (F)

We have:

reactance:  $$\small{\text{$X_C = 8800\ \Omega$}}$$

frequency:  $$\small{\text{$f = 830000\ \rm{Hz} $}}$$

capacitance:   $$\small{\text{$C=\dfrac{1}{2\cdot\pi\cdot f\cdot X_C} $}} \small{\text{$=\dfrac{1}{2\cdot\pi\cdot 830000\cdot (8800)} $}} \small{\text{$=0.00000000002179011\ \rm{F} = 21.79011\ \rm{pF}$}}$$