square root problem

Question

0

584

1

how do we solve: sqrt(x^2-10x+25)=4 ?

Guest Nov 19, 2015

+26396

+15

Best Answer

how do we solve: sqrt(x^2-10x+25)=4 ?

$x^2-10x+25 = (x-5)^2$

$\begin{array}{rcll} \sqrt{x^2-10x+25} &=& 4 \\ \sqrt{(x-5)^2} &=& 4 \\ x-5 &=& 4\\ x &=& 4+5\\ x &=& 9 \end{array}$

heureka Nov 19, 2015

heureka · Answer 1 · 2015-11-19T05:25:37

how do we solve: sqrt(x^2-10x+25)=4 ?

$x^2-10x+25 = (x-5)^2$

$\begin{array}{rcll} \sqrt{x^2-10x+25} &=& 4 \\ \sqrt{(x-5)^2} &=& 4 \\ x-5 &=& 4\\ x &=& 4+5\\ x &=& 9 \end{array}$