sqaure root of 2x times square root of 64x

sqaure root of 2x times square root of 64x

$\sqrt{2x}\times \sqrt{64x}$ = $\sqrt{2\times 64x^{2} }= 8x\times \sqrt{2}$

= 11.3137x

$\sqrt{2x}\times \sqrt{64x}\\ = \sqrt{2}\times \sqrt{x}\times \sqrt{64}\times \sqrt{x}\\ = 8\times \sqrt{2}\times (\sqrt{x})^2\\ =8\sqrt2\;x$

Same as asinus's answer.