+360 1. Given the functions f(x)=1/x−3 (to the side of the fraction) +1 and g(x)=1/x+4 (to the side of the fraction)+3 .
Which statement describes the transformation of the graph of function f onto the graph of function g?
Options:
The graph shifts 2 units right and 7 units down.
The graph shifts 7 units right and 2 units down.
The graph shifts 2 units left and 7 units up.
The graph shifts 7 units left and 2 units up.
2.
What are the coordinates of the hole in the graph of the function f(x) ?
f(x)=x^2+3x−28/x+7
_____, _______
Thanks again. Happy Valentnes day.
+128408 First one
f(x) = 1 / (x - 3) + 1
g(x) = 1 / (x + 4) + 3
g(x) is translated 7 units to the left and 2 units up
Second one
(x^2 + 3x - 28) / ( x + 7) factor the numerator
[ ( x + 7) (x - 4) ] /( x + 7) cancel the ( x + 7)
x - 4
Since x = - 7 makes the denominator of the original fraction = 0.....the "hole" occurs at x = -7
To find the y coordinate of the "hole"...put -7 into x - 4 for x = - 7 - 4 = -11
So....the "hole" occurs at ( -7, -11)
+360 Thank you so much for your help! As always, your explanations are always easier to understand. :)
