-x + 2/5 = -3/5y
3y = -18/11x +51/11
−x+25=−35yx=25+35y=15(2+3y)now look at the second equation3y=−1811x+5111substitute in the first result3y=−1811(15(2+3y))+5111
3y=−1855(2+3y)+51113y+18⋅355y=−18⋅255+511121955y=21955y=1x=15(2+3y)=1(x,y)=(1,1)