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avatar+1124 

The second one for today is also about solving x

 

7x29=1

 

I tried this:

Multiply both sides by 7, I get:

49x29=7

72(x29)=7

2(x29)=1

2x218=1

then proceed untill

x2=9,5

 

The answer after this is incorrect. I was thinking of something else: After this line:

2(x29)=1, do this:

2(x+3)(x3)=1

 

going further yields also a wrong answer. Please help me?..

 Nov 1, 2017
 #1
avatar+26399 
+3

The second one for today is also about solving

7x29=1

 

7x29=1|77x297=77x2971=7|abac=ab+c7x29+1=77x28=71x28=1x2=9|square root both sidesx=±3

 

laugh

 Nov 1, 2017
 #2
avatar+1124 
+2

Heureka,

 

thank you kindly...something so small that i just do not think of...I do appreciate your help!

juriemagic  Nov 1, 2017
 #3
avatar+130503 
+4

7x^2 - 9  = 1    ...... note  1  =  70

 

 So

 

7x^2 - 9  =  70     since the bases are the same, solve for the exponrents

 

x^2  - 9  = 0

 

(x + 3) (x - 3)  = 0

 

Set each factor to 0   and solve for x  ...so   ....x = 3   or  x = - 3

 

 

cool cool cool

 Nov 1, 2017

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