Loading [MathJax]/jax/output/SVG/jax.js
 
+0  
 
0
594
1
avatar

Solve x divided by negative six is greater than three for x.

x is greater than negative eighteen

x is less than negative two

x is less than negative eighteen

x is greater than negative two

 Jul 15, 2014

Best Answer 

 #1
avatar+5478 
+26

First. write this scenario into an inequality:

x/-6 > 3

Now multiply both sides by -6.

x < 3 * -6

(The inequality symbol is flipped because you are dividing by a negative number).

x < -18, so it would be the third choice.

 

To check, you can plug in a number less than -18 for x, such as -19.

196=196=3.1666666666666667

3.16666... is greater than 3, so the answer is correct.

 Jul 15, 2014
 #1
avatar+5478 
+26
Best Answer

First. write this scenario into an inequality:

x/-6 > 3

Now multiply both sides by -6.

x < 3 * -6

(The inequality symbol is flipped because you are dividing by a negative number).

x < -18, so it would be the third choice.

 

To check, you can plug in a number less than -18 for x, such as -19.

196=196=3.1666666666666667

3.16666... is greater than 3, so the answer is correct.

kitty<3 Jul 15, 2014

0 Online Users