My second one for today:
Solve x:
2 Log x + 2 = log 900
I said:
\(Log X^2 + 2 = Log 30^2\)
\(2Log x - 2Log 30 = -2\)
\(2Log {x \over 30} = -2\)
\(60Logx = -60\)
\(Log x = -1\)
\(x=10^-1\)
\(x= {1 \over 10}\)
Is this correct?
You go wrong on your fourth line. Check: 2log(1/10) +2 =0 log(900) = 2.954
\(2log_{10}x+2=log_{10}900\\ 2log_{10}x+2=log_{10}30^2\\2log_{10}x+2=2log_{10}30\\ log_{10}x+1=log_{10}30\\log_{10}x+log_{10}10=log_{10}30\\log_{10}(10x)=log_{10}30\\ 10x=30\\x = 3\)
Alan,
thanks again...I understand my error...thanx a million!
+1124 
