+579 \(\mathrm{Use\:the\:following\:identity}:\quad \sin \left(s\right)-\sin \left(t\right)=2\cos \left(\frac{s+t}{2}\right)\sin \left(\frac{s-t}{2}\right)\)
\(\sin \left(88^{\circ \:}\right)-\sin \left(32^{\circ \:}\right)=2\cos \left(\frac{88^{\circ \:}+32^{\circ \:}}{2}\right)\sin \left(\frac{88^{\circ \:}-32^{\circ \:}}{2}\right)\)
\(2\cos \left(60^{\circ \:}\right)\sin \left(28^{\circ \:}\right)\)
\(2\cdot \frac{1}{2}\sin \left(28^{\circ \:}\right)\)
\(\sin(28)\)
-Vinculum
+128408 THX, Vinculum !!!!
Also.......using the identity for sin (A + B) and sin (A - B) ........
sin (88) - sin (32)
sin ( 60 + 28) - sin (60 - 28) =
[sin (60)cos(28) + sin (28)cos (60)] - [ sin (60) cos (28) - sin (28) cos (60 ] =
2 sin( 28) cos (60) =
2 sin (28) (1/2) =
sin (28)
