Simplify and leave in radical form

$\sqrt[2]{3}\cdot\sqrt[3]{2}\ =\ 3^{\frac12}\cdot2^{\frac13}\ =\ 3^{\frac36}\cdot2^{\frac26}\ =\ (3^3\cdot2^2)^{\frac16}\ =\ (27\cdot4)^{\frac16}\ =\ (108)^{\frac16}\ =\ \sqrt[6]{108}$

√3 *∛2  =

(3)^1/2  * (2)^(1/3)  =

(3)^(3/6) * 2^(2/6)  =

(3^3)^(1/6)  *  (2^2)^(1/6)  =

(27)^(1/6) * (4)^(1/6)  =

(27 * 4)^(1/6)    =

(108)^(1/6)   =

⁶√108