Simple question #5

Hallo guest

Solve for x, showing your work every step of the way.

3(x + 4) + 5x - 7 = 6 + 2x - 2(x - 4)

$\begin{array}{rcll} 3(x + 4) + 5x - 7 &=& 6 + 2x - 2(x - 4) \\ 3x + 3\cdot 4 + 5x - 7 &=& 6 + 2x - 2x -2\cdot (-4) \qquad & | \qquad 3\cdot 4 = 12\\ 3x +12 + 5x - 7 &=& 6 + 2x - 2x -2\cdot (-4) \qquad & | \qquad -2\cdot (-4) = +8\\ 3x +12 + 5x - 7 &=& 6 + 2x - 2x +8 \qquad & | \qquad 2x - 2x = 0\\ 3x + 12 + 5x - 7 &=& 6 + 0 +8\\ 3x + 12 + 5x - 7 &=& 6 +8 \qquad & | \qquad 6 +8 = 14\\ 3x + 12 + 5x - 7 &=& 14 \\ 3x + 5x + 12 - 7 &=& 14 \qquad & | \qquad 12 - 7= 5\\ 3x + 5x + 5 &=& 14 \qquad & | \qquad 3x + 5x= 8x\\ 8x + 5 &=& 14 \qquad & | \qquad -5\\ 8x &=& 14 -5 \qquad & | \qquad 14 -5= 9\\ 8x &=& 9 \qquad & | \qquad :8\\ x &=& \frac{9}{ 8 }\\ \mathbf{x} &\mathbf{=}& \mathbf{1.125} \end{array}$