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Find the value of Sn=12+322+523+...+2n32n1+2n12n

 May 18, 2022
 #1
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Find the value of
Sn=12+322+523+...+2n32n1+2n12n

 

Let x=12

 

Sn=x+3x2+5x3+7x4+...+(2n3)xn1+(2n1)xnxSn=1x2+3x3+5x4+...+(2n5)xn1+(2n3)xn+(2n1)xn+1xxSn=x+2x2+2x3+2x4+...+2xn1+2xn(2n1)xn+1Sn(1x)=x+2(x2+x3+x4+...+xn1+xn)(2n1)xn+1x2+x3+x4+...+xn1+xn=x2xn+11xSn(1x)=x+2x2xn+11x(2n1)xn+1|1x=112=12Sn12=x+4(x2xn+1)(2n1)xn+1|2Sn=2x+8(x2xn+1)2(2n1)xn+1Sn=2x+8x28xn+12(2n1)xn+1Sn=2x+8x22xn+1(4+(2n1))Sn=2x+8x22xn+1(2n+3)Sn=2x(1+4xxn(2n+3))|x=12Sn=1+22n+32nSn=32n+32n

 

laugh

 May 19, 2022

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