the angles of a triangle are in the ratio 3:5:4 calculate the size of each angle
the angles of a triangle are in the ratio 3:5:4 calculate the size of each angle
Let α=angle1Let β=angle2Let γ=angle3γ=180∘−(α+β)
α:β:γ=α:β:180∘−(α+β)=3:5:4
(1):αβ=35α=35⋅β(2):αγ=α180∘−(α+β)=34α180∘−(α+β)=3443⋅α=180∘−(α+β)|α=35⋅β43⋅35⋅β=180∘−(35⋅β+β)45⋅β=180∘−85⋅β45⋅β+85⋅β=180∘125⋅β=180∘β=180∘⋅512β=75∘
α=35⋅β|β=75∘α=35⋅75∘α=45∘γ=180∘−(α+β)|α=45∘β=75∘γ=180∘−(45∘+75∘)γ=180∘−120∘γ=60∘
The angles of the triangle are 45∘, 75∘, 60∘
3 : 4 : 5 means that there are 3 + 4 + 5 = 12 equal parts
And the angles of a triangle sum to 180
So....one of these angles is 3/12 of this = 3/12 * 180 = 1/4 * 180 = 45°
And another of the angles is 4/12 of this = 4/12 * 180 = 1/3 * 180 = 60°
And the last angle must be 180 - 45 - 60 = 75°
I would just take the 12 parts, and divide 180 the correct amount of times. That 1st answer is over complicated. LOL!