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If 0 was in column a 1 in column b 2 in column c 3 in column d 4 in column e 5 in column f 6 in column g 7 in column a etc. in which column would 500 appear in

 Nov 6, 2015

Best Answer 

 #2
avatar+26397 
+30

If 0 was in column a 1 in column b 2 in column c 3 in column d 4 in column e 5 in column f 6 in column g 7 in column a etc. in which column would 500 appear in

 

nn(mod7)a00b11c22d33e44f55g66a70b81c92d103e114f125g136d5003

 

500 appear in d

laugh

 Nov 6, 2015
 #1
avatar
+5

Depends..... does your table go all the way to 'z' and then wrap around?  Or does it continue on past 'z' with new lettering scheme? Or does it wrap around at 'g'  ?

 Nov 6, 2015
 #2
avatar+26397 
+30
Best Answer

If 0 was in column a 1 in column b 2 in column c 3 in column d 4 in column e 5 in column f 6 in column g 7 in column a etc. in which column would 500 appear in

 

nn(mod7)a00b11c22d33e44f55g66a70b81c92d103e114f125g136d5003

 

500 appear in d

laugh

heureka Nov 6, 2015
 #3
avatar+118703 
+5

Thanks for both those great answers.

 

I am going to interprete it a little differently and let the alphabet go through to z

 

500 divided by 26 = 19 remainder 6

 

Only  the remainder is of any interest to us.  6 is g

 

0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
a b c d e f g h i j k l m n o p q r s t u v w x y z

    

 

 

My answer is not better than Heureka's, we have just that we have interpreted the question differently :))

 Nov 6, 2015
edited by Melody  Nov 6, 2015

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