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Pearl writes down seven consecutive integers, and adds them up. The sum of the integers is equal to 28/5 times the largest of the seven integers. What is the smallest integer that Pearl wrote down?

 Jun 13, 2024

Best Answer 

 #1
avatar+1950 
+1

We can set up an equation to help us solve this problem. Let's define a variable. 

Let n be the smallest  number. We have n+n+1+n+2.......n+6=7n+21

 

Now, this sequence adds up to 28/5 times the largest number, n + 6, so we can write the equation

7n+21=28/5(n+6)

 

From here, we just solve for n. We have

7n+21=285n+168/57/5n=63/5

 

Now, multiplying both sides by the reciprocol of 7/5, we get

n=63557=9

 

So 9 is our final answer!

 

Thanks! :)

 Jun 13, 2024
 #1
avatar+1950 
+1
Best Answer

We can set up an equation to help us solve this problem. Let's define a variable. 

Let n be the smallest  number. We have n+n+1+n+2.......n+6=7n+21

 

Now, this sequence adds up to 28/5 times the largest number, n + 6, so we can write the equation

7n+21=28/5(n+6)

 

From here, we just solve for n. We have

7n+21=285n+168/57/5n=63/5

 

Now, multiplying both sides by the reciprocol of 7/5, we get

n=63557=9

 

So 9 is our final answer!

 

Thanks! :)

NotThatSmart Jun 13, 2024

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