Pearl writes down seven consecutive integers, and adds them up. The sum of the integers is equal to 28/5 times the largest of the seven integers. What is the smallest integer that Pearl wrote down?
We can set up an equation to help us solve this problem. Let's define a variable.
Let n be the smallest number. We have n+n+1+n+2.......n+6=7n+21
Now, this sequence adds up to 28/5 times the largest number, n + 6, so we can write the equation
7n+21=28/5(n+6)
From here, we just solve for n. We have
7n+21=285n+168/57/5n=63/5
Now, multiplying both sides by the reciprocol of 7/5, we get
n=635⋅57=9
So 9 is our final answer!
Thanks! :)
We can set up an equation to help us solve this problem. Let's define a variable.
Let n be the smallest number. We have n+n+1+n+2.......n+6=7n+21
Now, this sequence adds up to 28/5 times the largest number, n + 6, so we can write the equation
7n+21=28/5(n+6)
From here, we just solve for n. We have
7n+21=285n+168/57/5n=63/5
Now, multiplying both sides by the reciprocol of 7/5, we get
n=635⋅57=9
So 9 is our final answer!
Thanks! :)