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2^x * 5^y, = 100 2^y 5^x = 1000 x+y=?

 Nov 23, 2016
 #1
avatar+26398 
+5

2^x * 5^y = 100

2^y * 5^x = 1000

x+y = ?

 

2x5y=1002x5y=1022y5x=10002y5x=103(2x5y)(2y5x)=1021032x2y5y5x=102+32x2y5y5x=1052x+y5y+x=105(25)x+y=10510x+y=105x+y=5

 

laugh

 Nov 23, 2016
 #2
avatar
0

2^x * 5^y, = 100 2^y 5^x = 1000 x+y=?

 

Using Newton-Raphson method:

x= (2 log(2) - 3 log(5))/(log(2) - log(5)) ≈ 3.75647

y= (3 log(2) - 2 log(5))/(log(2) - log(5)) ≈1.24353

x + y = 3.75647 + 1.24353 =5

 Nov 23, 2016
 #3
avatar+9676 
0

Another approach ---- take log each side.

2x5y=100xlog2+ylog5=2

2y5x=1000ylog2+xlog5=3

After this we may solve it like a linear equation!!

Add the 2 equations up:xlog2+ylog2+xlog5+ylog5=5(x+y)(log2+log5)=5Factorization(x+y)(log10)=5Property of logarithmsx+y=5

 Nov 24, 2016

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