If I choose four cards from a standard -card deck, with replacement, what is the probability that I will end up with one card from each suit, or four Aces?
there are 4x3x2 ways to get one from each suit, which includes aces.
there are 4x4x4x4 ways in total, so (4x3x2)/(4x4x4x4)=$\boxed{\dfrac3{32}}$