A bag contains 6 red marbles, 5 blue marbles and 8 green marbles. If three marbles are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that all three marbles drawn will be green?
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A bag contains 6 red marbles, 5 blue marbles and 8 green marbles. If three marbles are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that all three marbles drawn will be green?
The probability of the 1st marble being green is 8 / 19
If the 1st marble was green, that leaves 7 in the bag
The probability of the 2nd marble being green is 7 / 18
If the 2nd marble was green, that leaves 6 in the bag
The probability of the 3rd marble being green is 6 / 17
The probability of all three occurring is (8 / 19) x (7 x 18) x (6 / 17) = 336 / 5814
336 / 5814 = 0.05779 which is 5.779% which rounds to 5.8%
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