How do I deal with this probability
Right triangle XYZ has legs of length XY = 12 and YZ = 6. Point D is chosen at random within the triangle XYZ. What is the probability that the area of triangle XYD is at most 20?
This problem has already been answered :)
https://web2.0calc.com/questions/cphill-help-pls
if that is incorrect I can come back and attempt to recomplete a solution
Note that that △XYD has a base of 12. This means that the height of the triangle can be at most 10/3.
We want to find the shaded region's area over the triangle's area, which is 36.
The area of the shaded region is the same as the area of the triangle minus the area of the non-shaded region.
The nonshaded region is a right triangle similar to △XYZ with a scale factor of 4/9, so its area is 36×(49)2=649.
This means that the shaded region has an area of 36−649=2609, so the probability is just 260936=6581