probability

Joshua rolls two dice to form a two-digit integer.
If the number on the first die represents the tens digit
and the number on the second die represents the units digit,
what is the probability that the integer formed is divisible by 8?

$\begin{array}{|c|c|c|c|c|c|c|} \hline & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline 1 & 11 & 12 & 13 & 14 & 15 & \color{red}16 \\ \hline 2 & 21 & 22 & 23 & \color{red}24 & 25 & 26 \\ \hline 3 & 31 & \color{red}32 & 33 & 34 & 35 & 36 \\ \hline 4 & 41 & 42 & 43 & 44 & 45 & 46 \\ \hline 5 & 51 & 52 & 53 & 54 & 55 & \color{red}56 \\ \hline 6 & 61 & 62 & 63 & \color{red}64 & 65 & 66 \\ \hline \hline \end{array}$

The probability is $\dfrac{5}{36}$ or $13.9~\%$