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Each of the digits​ 0-9 is written on a slip of​ paper, and the slips are placed in a hat. If 5 slips of paper are selected at​ random, determine the probability that the 5 numbers selected are greater than 3.

 Aug 10, 2021
 #1
avatar+191 
+3

The chance of the 1st selection greater than 3 is 6/10 or 3/5

The chance of the 2nd selection greater than 3 is 5/9

The chance of the 3rd selection greater than 3 is 4/8 or 1/2

The chance of the 4th selection greater than 3 is 3/7

The chance of 5th selection greater than 3 is 2/6 or 1/3

 

Multiply all chances together we get: 1/42

 

So, the answer is 1/42 chance the 5 numbers selected are greater than 3

 Aug 10, 2021
 #2
avatar+3 
+2

I agree!

1/42 chance is the answer. The 5 numbers chosen are all bigger than 3.

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 Aug 10, 2021

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