I don't get these questions. please help me with them, thanks :)
first question
second question:
1150 + 150n n from 1 to 12
n = 12 an = 1150+1800=2950
s= n (a1+ an)/2
12(1150+2950)/2=24600
+1011 Well the resturant makes 2950 in 12 months here is the math\
Well the resturant starts with $1,300
so each month it earns $150
so
150*11=1650
Then
1,650 = 2,950 a year I should say that is how much it makes in 12 months
1,300 =
Hope This helps (;
Sum =N/2[2*F + (N - 1)*D, where N=12, F=1,300, D=150
Sum =12/2[2*1,300 + (12 - 1)*150
Sum =6[2,600 + (11*150)]
Sum =6[2,600 + 1,650]
Sum =6*[4,250]
Sum=$25,500 - Restaurant's profit in 12-month period.
+434 Because they get a 150 profit every year you took it as if th profit started in febuary..
+1011 Well two people agreed on mine it is not right to say mine is wrong without prof 2 people said mine was right 2
+434 Well I have no Idea which guest is talking but it was both guest users the equation Idea I though was an excellent way to put it but unfortuanatly 6th graders aren't familar with full algrbra concepts yet...
I'm the one who posted the question that you are all replying to :) So I'm the one asking HiyinLink what the correct answer is.
+434 Cool well good XD yup I liked the equation it was an excellent Idea we can just simplify it for him if he's not familiar...
The subject this question is from is arithmetic series & applications, and i'm in algebra 2.
+434 I might be able to help you tommorrow I GTG though if not someone else that may get to it before me...
+434 But trick fo the final 1 thre is an increase of three evry row so going down sven you can do it like this you just addd the new values everytime you go down..
