Consider p(x)=ax^2-5x+6 and q(x)=bx^2+3x-2.
If p(x) * q(x) has a 20x^3 term and a 30x^2 term, determine a+b.
+170 We have p(x)q(x)=(ax2−5x+6)(bx2+3x−2), so 20=3a−5b and 30=−2a+6b−15. Solving the system of equations gives a=43.125 and b=21.875, so a+b=65.
+170 We have p(x)q(x)=(ax2−5x+6)(bx2+3x−2), so 20=3a−5b and 30=−2a+6b−15. Solving the system of equations gives a=43.125 and b=21.875, so a+b=65.
