Can you, and how do you simplify this further?
d=√x2+b2a2
d=√x2+b2a2d=√x2+(ba)2
d = sqrt ( x^2 + b^2 / a^2) =
sqrt ( [a^2x^2 + b^2] / a^2 ) =
sqrt ( [ax]^2 + b^2 ) / a [whether this is any "simpler," or not, could be debated !!!! ]