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$If $f(x) = 2x + 3$ and $g(x) = 3x - 2$ find $\frac{f(g(f(2)))}{g(f(g(2)))}$. Express your answer in the form $\frac{a}{b}$.$

Please help!

Guest Jun 18, 2019

Best Answer

+9488

+2

f(x) = 2x + 3 and g(x) = 3x - 2

f( g( f(2) ) ) = f( g( 7 ) ) = f( 19 ) = 41

g( f( g(2) ) ) = g( f( 4 ) ) = g( 11 ) = 31

And so...

$\dfrac{f(\ g(\,f(2)\,)\ )}{g(\ f(\,g(2)\,)\ )}\ =\ \dfrac{41}{31}$ _

hectictar Jun 18, 2019

1⁺⁰ Answers

+9488

+2

Best Answer

f(x) = 2x + 3 and g(x) = 3x - 2

f( g( f(2) ) ) = f( g( 7 ) ) = f( 19 ) = 41

g( f( g(2) ) ) = g( f( 4 ) ) = g( 11 ) = 31

And so...

$\dfrac{f(\ g(\,f(2)\,)\ )}{g(\ f(\,g(2)\,)\ )}\ =\ \dfrac{41}{31}$ _

hectictar Jun 18, 2019

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