What is the right equation?
Should be a, if i am not mistaken
f(x)=(x-2)^2(x+1)(x-3)
Which of the choices have roots (i.e. are equal to zero) at x = -1 2 and 3 ?
that makes it pretty easy......
ahh yes
i did it a different way
this is easier though
It's f(x)=(x-2)^2(x+1)(x-3) because it passes y=0 at x=-1,2,3 so the solution of f(x)=0 is -1,2,3.
+36916 
+8 
