Please help solve

Divide and simplify.

3x-15/121 ÷ x-5/33

$\begin{array}{rcl} \dfrac{ \frac{3x-15}{121} }{ \frac{x-5}{33} } &=& \dfrac{ \frac{3(x-5)}{121} }{ \frac{x-5}{33} } \\\\ &=& \frac{3(x-5)}{121} \cdot \frac{33}{(x-5)} \\\\ &=& \frac{3\cdot 33}{121} \\\\ &=& \frac{99}{121} \\\\ &=& \frac{9}{11} \end{array}$