9.) Transform each polar equation to an equation in rectangular coordinates and identify its shape:\
r = (4 / (2cosθ - 3sinθ));
10.) compute the modulus and argument of each complex number.
a.) -5
b. )-5 + 5i
9.)
r = 42cosθ−3sinθ r(2cosθ−3sinθ) = 4 2rcosθ−3rsinθ = 4 2x−3y = 4 becausex=rcosθandy=rsinθ 2x = 4+3y 2x−4 = 3y 23x−43 = y y = 23x−43
This is the equation of a line with a slope of 23 and a y-intercept of −43 .
Check: https://www.desmos.com/calculator/7dq2bqym7k
(You can show or hide the second equation by clicking the gray circle to the left of it. )
9.)
r = 42cosθ−3sinθ r(2cosθ−3sinθ) = 4 2rcosθ−3rsinθ = 4 2x−3y = 4 becausex=rcosθandy=rsinθ 2x = 4+3y 2x−4 = 3y 23x−43 = y y = 23x−43
This is the equation of a line with a slope of 23 and a y-intercept of −43 .
Check: https://www.desmos.com/calculator/7dq2bqym7k
(You can show or hide the second equation by clicking the gray circle to the left of it. )
10.) compute the modulus and argument of each complex number.
a.) -5
We have the form -5 + 0i
The modulus is √ [ (-50^2 + 0^2 ] = √25 = 5
The argument is θ so tan θ = 0 / -5 = pi
b. ) -5 + 5i
Modulus = √[ (-5)^2 + (5)^2 ] = √ [ 50] = 5√2
The argument is θ so tan θ = 5/-5 = - 1 = 3pi/4