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For all complex numbers z, let f(z)={z2 if z is not real,z2 if z is real.

Find f(f(f(f(1+i)))).

 Aug 20, 2018
 #1
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Let's define z0=1+i. Then we want to find f(f(f(f(z0)))).

 

z is not real, so we havef(z0)=z20=(1+i)2=1+2i+i2=1+2i1=2i.

So f(z0)=2i is not real either, and therefore f(f(z0))=f(z0)2=(2i)2=4.

 

Now things change, because f(f(z0))=4 is real and so f(f(f(z0)))=(4)2=16.

This is still real, so we have finally:

 

f(f(f(f(z0))))=(16)2=256

 Aug 20, 2018
 #2
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Thanks! Your right!

Lightning  Aug 20, 2018

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