Physics

at an angle of*

Light of wavelength 619 nm passes through a double slit and makes its first max (m=1) at ab abgke if 0.226 deg. What is the separation of the slits, d, IN MILLIMETERS? Rearrange and solve, please. 

$d\sin(\theta)= m\lambda$

$\begin{array}{rcll} Let\ \lambda &=& 619\ nm \\ \lambda &=& 619 \cdot 10^{-9}\ m \\ \lambda &=& 619 \cdot 10^{-6}\ mm \\\\ Let\ \theta &=& 0.226^{\circ} \\ \end{array}$

$\begin{array}{|rcll|} \hline d\sin(\theta) &=& m \lambda \\ d &=& m\cdot \frac{\lambda}{\sin(\theta)} \quad & | \quad m=1 \\ d &=& 1\cdot \frac{619 \cdot 10^{-6}\ mm }{\sin(0.226^{\circ})} \\ d &=& 156929.997726 \cdot 10^{-6} \ mm \\ d &=& 0.156929997726 \cdot 10^{6}\cdot 10^{-6} \ mm \\ d &=& 0.156929997726 \ mm \\ \hline \end{array}$