+2448 Assume an 8 kg bowling ball moving at 2 m/s bounces off a spring at the same speed that it had before bouncing. a) what is its momentum of recoil? b) what is its change in momentum? (Hint: What is the change in temperature when something goes from 1 to -1 degrees? c) If the interaction with the spring occurs in 0.5s, calculate the average force the spring exerts on it.
+6252 conservation of momentum is a vector equationassume the velocity of the bowling ball is vi=−2ˆimoving left along the x-axis if you likewhen it recoils it's given to have the same speedbut now it's velocity will be vf=+2ˆiit's momentum of recoil is just m→v=8kg⋅(2ˆi m/s)=16ˆi kg⋅m/sthe change is just twice this since it was originally exactly negative thisso Δmv=32ˆi kg⋅m/s
F=d mvdtand in this case this meansF=ΔmvtF=32ˆi0.5=64ˆi Nnote that F is a vector. It has direction as expected
.+6252 conservation of momentum is a vector equationassume the velocity of the bowling ball is vi=−2ˆimoving left along the x-axis if you likewhen it recoils it's given to have the same speedbut now it's velocity will be vf=+2ˆiit's momentum of recoil is just m→v=8kg⋅(2ˆi m/s)=16ˆi kg⋅m/sthe change is just twice this since it was originally exactly negative thisso Δmv=32ˆi kg⋅m/s
F=d mvdtand in this case this meansF=ΔmvtF=32ˆi0.5=64ˆi Nnote that F is a vector. It has direction as expected
