Find the vertex of the parabola x = -2y^2 + 12y - 15.
We complete the square to get \(y=-2(y-3)^2+3\). The vertex is (h, k). Therfore the vertex of the parabola \(x = -2y^2 + 12y - 15\ \text {is} \ \boxed{(3, 3)}.\)
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