The vertex of the parabola described by the equation 3y=2x^2+16x+28 is (m, n). What is m+n?
+37167 Manipulte into vertex form of a parabola
3y=2x^2+16x+28
3/2 y = x^2 + 8x + 14
= (x+4)^2 - 2
y = 2/3 (x+4)^2 - 4/3 vertex is then -4, - 4/3 added = - 5 1/3
