+937 
Answer: 70
I tried this question by drawing pictures, but it didn't work out.
+6252 It can't be 70Aboard=322=1024 sq inAphoto=3⋅5=15 sq in102415=68+415so with no overlapping 68 is the maximum possible, and is probably not attainable
.
+9490 As Rom said, there is definitely no way to put 70 pictures on the board.
68 pictures is the maximum possible, and here is a way to do that:
However, if you can't rotate the pictures 90 degrees, then the maximum possible is
floor( 32 / 3 ) * floor( 32 / 5 ) = 10 * 6 = 60
+937 I don't know guys. Out of all the questions I've looked at made by this organization, their answers are always correct. Also, this was on a math contest taken by all middle schoolers in the U.S., so if the answer is wrong, then a student has to have already told them and they would have fixed it already. I also got 68, but these questions tend to have a creative way to solving them. Still, you guys have really great solutions and I agree with your reasoning why 68 is the maximum possible.
+9490 Hmmm....even if you cut the pictures into 1 inch by 1 inch squares, there's just not enough square inches on the board to fit 70 pictures worth.
number of square inches on the board = 32 * 32 = 1024
number of square inches of 70 pictures = 70 * 3 * 5 = 1050
Are you sure it says 70 and not 60 ?
If so, maybe you can be the one to report the error in this question. Yes it is weird and unlikely they'd have it wrong, but it's not impossible.
