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No calc please

 Jun 8, 2019

Best Answer 

 #1
avatar+9488 
+3

Let's say it starts wih  x  fish.

 

number of fish left after John leaves _ = 23(x1) = 23x23
number of fish left after Joe leaves

 

 

 

= 23( 23x23 1) = 49x109
number of fish left after _James_ leaves

 

= 23( 49x109 1) = 827x3827

 

The smallest positive integer value of  x  that makes  827x3827  a positive integer is  25 .

 

By looking at a graph we can check this:  https://www.desmos.com/calculator/mivvh3t6in

 

So the minimum possible number of fish before John threw out the first fish is  25 .

 Jun 8, 2019
 #1
avatar+9488 
+3
Best Answer

Let's say it starts wih  x  fish.

 

number of fish left after John leaves _ = 23(x1) = 23x23
number of fish left after Joe leaves

 

 

 

= 23( 23x23 1) = 49x109
number of fish left after _James_ leaves

 

= 23( 49x109 1) = 827x3827

 

The smallest positive integer value of  x  that makes  827x3827  a positive integer is  25 .

 

By looking at a graph we can check this:  https://www.desmos.com/calculator/mivvh3t6in

 

So the minimum possible number of fish before John threw out the first fish is  25 .

hectictar Jun 8, 2019

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