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Let f(n) return the number of distinct ordered pairs of positive integers (a,b)  such that for each ordered pair, a2+b2=n . Note that when ab,(a,b),  and (b,a) are distinct. What is the smallest positive integer n for which f(n)=3 ?

 

Please write an approach to get to the answer.

 Oct 21, 2021
 #1
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The only way to do this is brute force.

 

The smallest n that works is 200: 200 = 2^2 + 14^2 = 10^2 + 10^2 = 14^2 + 2^2

 Oct 21, 2021
 #2
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That is not correct, the answer is 50

 Oct 21, 2021
 #3
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Hello sherwyo,

 

how about saying Thanks to him?

I think that's not polite to each other.

 

Straight

 Oct 22, 2021

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