+0  
 
0
8
2
avatar+569 

Find the greatest prime divisor of the value of the arithmetic series
1 + 2 + 3 + \dots + 135 + 136 + 137 + 138 + 139 + 140.

 Dec 16, 2024
 #2
avatar+1950 
+1

So for this problem, let's use the arithmetic series formula.

 

We find the sum is , which is Now that we have a factorization, we can easily find the greatest prime divisor.

 

The prime factorization is , so the greatest prime divisor is 47.

 

Thanks! :)

 Dec 17, 2024
edited by NotThatSmart  Dec 17, 2024

1 Online Users