If 3x+7≡11(mod16),
then 2x+11 is congruent (mod16) to what integer between 0 and 15, inclusive?
3x+7≡11(mod16)|−73x≡11−7(mod16)3x≡4(mod16)|:3x≡43(mod16)x(mod16)≡43
2x+11(mod16)≡2∗43+11(mod16)≡83+11(mod16)≡83+333(mod16)≡413(mod16)|41≡9(mod16)≡93(mod16)2x+11(mod16)≡3(mod16)
