need to find the one equivalent to n+3n+2n(squared) using distributive property

need to find the one equivalent to n+3n+2n(squared) using distributive property

2n(n+2)

2n(n+1)

n(n+2)

2n(2n+2)

$$n+3n+2n^2 \\ = n(1+3+2n) \\ = n ( 4+2n ) \\ = n * 2(2+n) \\ =2n(n+2)$$

the answers in the one before are the options. sorry!

nevermind it wasnt an answer