(-81)^\frac{1}{4}
Firstly there is no real solution for this because no real number to the power of 4 is going to be negative.
But I will give you the complex solution :)
(−81)14=(−1)14∗(81)14=(−1)14∗3=((−1)12)12∗3=i12∗3
Now
√i=√1+2i−12=√1+2i+i22=√(1+i)22=1+i√2
=3∗√i=3(1+i)√2=3√2(1+i)2
I forgot to finish it............this is one answer but there are 3 more...
I see Heureka is answering so I expect he will give the other ones. :)
Thanks in advance Heureka
Hello Melody,
you set -1 to i2 but i think this is not allowed, if (-1) is a complex number.
only (-1) real is i^2 and (-1) complex is eiπ.
This way is okay i2→−1
This way is not allowed −1→i2
Hi Heureka,
I certainly accept that your knowledge of mathematics is far superior to mine but I do not get why I cannot do this.
Our answers are the same.
I suppose it is some mathematics nuance that has gone over my head :(
But thank you