You are given the following reaction equation.
2 Fe(aq) + 3 CuCl2(aq) --> 2 FeCl3(aq) + 3 Cu(s)
If 0.0125 moles of iron solid reacted, how many moles of copper solid would be produced ?
Put your answer in the form of a.bc x 10-d and input your values for a,b,c and d with no spaces or punctuation.
+15080 If 0.0125 moles of iron solid reacted, how many 2 moles of copper solid would be produced ?
Hello Guest!
2Fe+3CuCl2−−>2FeCl3+3Cu
relative atomic mass
Fe 55.85
Cu 63.54
2⋅55.85g Fe ˆ= 3⋅63.54g Cu111.7g Fe ˆ= 190.62g Cu0.0125 mol:2 mol=x:190.62g Cux=190.62⋅0.01252 g Cux=1.91375g Cu⋅mol63.54g
x=1.875×10−2mol Cu
1.875×10−2moles of Copper solid would be produced.
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+2234 Hello Asinus:
Your solution is correct, but your method is overkill. The question introduces a molar ratio and asks for the number of moles. Molar mass is not needed here, only a basic ratio formula.
Question (restated in active voice): Two (2) moles of Fe (iron) react to produce three (3) moles of Cu (copper). How many moles of copper precipitate, if 0.0125 moles of iron react?
Solution:
Molar ratio: 2Fe:3Cu=0.0125Fe:XCu; solve for X.0.0125Fe∗3Cu2Fe=0.01875Cu→1.875x10−2molesCu
GA
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+15080 Oh wow !
Hello GingerAle!
I made a masterpiece there. Think crookedly and still get the right result! I woke up at 3 a.m. and never fell asleep again. I turned too much to chemistry and not so much to mathematics. Sorry, it was three o'clock in the morning. I recommend the studends your method! Thanks for the simple solution!
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